admin 发表于 2016-8-5 16:42:00

shell获取日期序列

#!/bin/sh

datebeg=20160701
dateend=20160731
beg_s=`date -d "$datebeg" +%s`
end_s=`date -d "$dateend" +%s`
while [ "$beg_s" -le "$end_s" ]
do
    day=`date -d @$beg_s +"%Y%m%d"`
    echo "================ rollback [ $day ] ================"

    #/home/xiaoju/local/php-fpm/bin/php run.php dm_car_order_fee_stat $day -r
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    beg_s=$((beg_s+86400))
done


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